[hot] [역학] 재료역학(Mechanics of Materials) solution - James M.Gere 6th ed…
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Download : 재료역학.zip
863.9mm2
재료역학(Mechanics of Materials) 솔루션 - James M.Gere 6th edition 입니다. (a) If the measured strain is 550 106, what is the
P 200 lb
P P
Rounding, we get
[이용대상]
in.2 ≤
strains in the longitudinal direction.
(b) If the compressive stress in the bar is intended to be 40
P P
(0.25 in.)2 4074 psi
Weight density: 490 lb/ft3
재료역학(Mechanics of Materials) 솔루션 - James M.Gere 6th edition 입니다. [이용대상]
Solution 1.2-4 Aluminum tube in compression
MPa, what should be the load P?
eL (550 106)(400 mm)
역학, 재료, 공대, 솔루션
설명
smax
1
P = 200 lb
strain gage is placed on the outside of the bar to measure normal
(a) SHORTENING OF THE BAR
순서
L 110 ft
34.6 kN —
374.3 psi
Strain gage
[ (60 mm)2 (50 mm)2 ]
40 MPa
[d2
Solution 1.2-3 Long steel rod in tension
P A (40 MPa)(863.9 mm2)
144
레포트 > 공학,기술계열
P
재료역학(Mechanics of Materials) solution - James M.Gere 6th edition 입니다.
(b) COMPRESSIVE LOAD P
SECTION 1.2 Normal Stress and Strain 3
gL
4
A
d 1⁄4 in.
gL (490 lbft3)(110 ft)¢
P
챕터1부터 12까지 까지 입니다. 챕터1부터 12까지 까지 입니다.
d1 50 mm
Strain gage
A
2]
L
L = 400 mm
max 4450 psi —
d
ft2
e 550 106
(Volume)
Download : 재료역학.zip( 63 )
max 374 psi 4074 psi 4448 psi
2d1
L 400 mm
W Weight of rod
A
챕터1부터 12까지 까지 입니다.
mm is loaded in compression by forces P (see figure). The outside
d2 60 mm
P 200 lb
A
and inside diameters are 60 mm and 50 mm, respectively. A
[역학] 재료역학(Mechanics of Materials) solution - James M.Gere 6th edition 입니다.
AL
4
Problem 1.2-4 A circular aluminum tube of length L 400
4
shortening of the bar?
WP
200 lb
0.220 mm —
다.
